Base | Representation |
---|---|
bin | 110001010101111111110111… |
… | …1110011110001100110111111 |
3 | 2002220210001022101211200002102 |
4 | 1202223333233303301212333 |
5 | 423342134410004040242 |
6 | 4135035304442415315 |
7 | 160264526113063214 |
oct | 14253775763614677 |
9 | 2086701271750072 |
10 | 434031943424447 |
11 | 116328a05967955 |
12 | 4081a36b80153b |
13 | 158250626767c4 |
14 | 792738850bb0b |
15 | 352a278425e32 |
hex | 18abfefcf19bf |
434031943424447 has 2 divisors, whose sum is σ = 434031943424448. Its totient is φ = 434031943424446.
The previous prime is 434031943424353. The next prime is 434031943424461. The reversal of 434031943424447 is 744424349130434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434031943424447 - 230 = 434030869682623 is a prime.
It is a super-2 number, since 2×4340319434244472 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 434031943424392 and 434031943424401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434034943424447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217015971712223 + 217015971712224.
It is an arithmetic number, because the mean of its divisors is an integer number (217015971712224).
Almost surely, 2434031943424447 is an apocalyptic number.
434031943424447 is a deficient number, since it is larger than the sum of its proper divisors (1).
434031943424447 is an equidigital number, since it uses as much as digits as its factorization.
434031943424447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55738368, while the sum is 56.
The spelling of 434031943424447 in words is "four hundred thirty-four trillion, thirty-one billion, nine hundred forty-three million, four hundred twenty-four thousand, four hundred forty-seven".
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