Base | Representation |
---|---|
bin | 111111001010010110100… |
… | …010100110111000010101 |
3 | 120100221102220112212111001 |
4 | 333022112202212320111 |
5 | 1032103211302423014 |
6 | 13121545524543301 |
7 | 625405133364016 |
oct | 77122642467025 |
9 | 16327386485431 |
10 | 4340442623509 |
11 | 1423853784563 |
12 | 5a1259551b31 |
13 | 2563c05c2ba5 |
14 | 11011574b00d |
15 | 77d88e33974 |
hex | 3f2968a6e15 |
4340442623509 has 2 divisors, whose sum is σ = 4340442623510. Its totient is φ = 4340442623508.
The previous prime is 4340442623411. The next prime is 4340442623513. The reversal of 4340442623509 is 9053262440434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4128983360100 + 211459263409 = 2031990^2 + 459847^2 .
It is a cyclic number.
It is not a de Polignac number, because 4340442623509 - 213 = 4340442615317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4340442620509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170221311754 + 2170221311755.
It is an arithmetic number, because the mean of its divisors is an integer number (2170221311755).
Almost surely, 24340442623509 is an apocalyptic number.
It is an amenable number.
4340442623509 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340442623509 is an equidigital number, since it uses as much as digits as its factorization.
4340442623509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2488320, while the sum is 46.
The spelling of 4340442623509 in words is "four trillion, three hundred forty billion, four hundred forty-two million, six hundred twenty-three thousand, five hundred nine".
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