Base | Representation |
---|---|
bin | 111111001010110110000… |
… | …111111110111000011111 |
3 | 120100222210211122010202011 |
4 | 333022312013332320133 |
5 | 1032110302430433342 |
6 | 13122114254212051 |
7 | 625424226364513 |
oct | 77126607767037 |
9 | 16328724563664 |
10 | 4340972514847 |
11 | 1423aa58a7791 |
12 | 5a1386ab4027 |
13 | 256476312667 |
14 | 110165c84143 |
15 | 77dba703717 |
hex | 3f2b61fee1f |
4340972514847 has 2 divisors, whose sum is σ = 4340972514848. Its totient is φ = 4340972514846.
The previous prime is 4340972514793. The next prime is 4340972514877. The reversal of 4340972514847 is 7484152790434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4340972514847 - 239 = 3791216700959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4340972514791 and 4340972514800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4340972514877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170486257423 + 2170486257424.
It is an arithmetic number, because the mean of its divisors is an integer number (2170486257424).
Almost surely, 24340972514847 is an apocalyptic number.
4340972514847 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340972514847 is an equidigital number, since it uses as much as digits as its factorization.
4340972514847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27095040, while the sum is 58.
The spelling of 4340972514847 in words is "four trillion, three hundred forty billion, nine hundred seventy-two million, five hundred fourteen thousand, eight hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •