Search a number
-
+
4341104331953 is a prime number
BaseRepresentation
bin111111001010111101111…
…110110100110010110001
3120101000011000200010211012
4333022331332310302301
51032111040202110303
613122135323400305
7625430416664114
oct77127576646261
916330130603735
104341104331953
11142406324a944
125a1403083095
1325649771624c
1411017959857b
1577dc70905d8
hex3f2bdfb4cb1

4341104331953 has 2 divisors, whose sum is σ = 4341104331954. Its totient is φ = 4341104331952.

The previous prime is 4341104331913. The next prime is 4341104332031. The reversal of 4341104331953 is 3591334011434.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4145817232384 + 195287099569 = 2036128^2 + 441913^2 .

It is a cyclic number.

It is not a de Polignac number, because 4341104331953 - 228 = 4340835896497 is a prime.

It is a super-2 number, since 2×43411043319532 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4341104331953.

It is not a weakly prime, because it can be changed into another prime (4341104331913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170552165976 + 2170552165977.

It is an arithmetic number, because the mean of its divisors is an integer number (2170552165977).

Almost surely, 24341104331953 is an apocalyptic number.

It is an amenable number.

4341104331953 is a deficient number, since it is larger than the sum of its proper divisors (1).

4341104331953 is an equidigital number, since it uses as much as digits as its factorization.

4341104331953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 4341104331953 in words is "four trillion, three hundred forty-one billion, one hundred four million, three hundred thirty-one thousand, nine hundred fifty-three".