Base | Representation |
---|---|
bin | 1100101000100110011… |
… | …10101101101011010111 |
3 | 1112111112011200102220022 |
4 | 12110103032231223113 |
5 | 24103031231233421 |
6 | 531232424255355 |
7 | 43235520563102 |
oct | 6242316555327 |
9 | 1474464612808 |
10 | 434114321111 |
11 | 15811a242809 |
12 | 7017401155b |
13 | 31c24210c73 |
14 | 17022bdd739 |
15 | b45b82a7ab |
hex | 65133adad7 |
434114321111 has 2 divisors, whose sum is σ = 434114321112. Its totient is φ = 434114321110.
The previous prime is 434114321101. The next prime is 434114321119. The reversal of 434114321111 is 111123411434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434114321111 - 218 = 434114058967 is a prime.
It is a super-3 number, since 3×4341143211113 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434114321119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217057160555 + 217057160556.
It is an arithmetic number, because the mean of its divisors is an integer number (217057160556).
Almost surely, 2434114321111 is an apocalyptic number.
434114321111 is a deficient number, since it is larger than the sum of its proper divisors (1).
434114321111 is an equidigital number, since it uses as much as digits as its factorization.
434114321111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 26.
Adding to 434114321111 its reverse (111123411434), we get a palindrome (545237732545).
The spelling of 434114321111 in words is "four hundred thirty-four billion, one hundred fourteen million, three hundred twenty-one thousand, one hundred eleven".
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