Base | Representation |
---|---|
bin | 10011101111011101011000… |
… | …00011110100001100000110 |
3 | 12200201011021100211110201102 |
4 | 21313232230003310030012 |
5 | 21142231011003021042 |
6 | 232155130402100102 |
7 | 12100264555154243 |
oct | 1167565403641406 |
9 | 180634240743642 |
10 | 43412121142022 |
11 | 12917a826a6596 |
12 | 4a5168764a632 |
13 | 1b2b98ca04189 |
14 | aa122d2c85ca |
15 | 5043b0058b32 |
hex | 277bac0f4306 |
43412121142022 has 32 divisors (see below), whose sum is σ = 69788343889152. Its totient is φ = 20200461092064.
The previous prime is 43412121141971. The next prime is 43412121142079. The reversal of 43412121142022 is 22024112121434.
43412121142022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×434121211420222 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49335473 + ... + 50207699.
It is an arithmetic number, because the mean of its divisors is an integer number (2180885746536).
Almost surely, 243412121142022 is an apocalyptic number.
43412121142022 is a deficient number, since it is larger than the sum of its proper divisors (26376222747130).
43412121142022 is a wasteful number, since it uses less digits than its factorization.
43412121142022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 901532.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 43412121142022 its reverse (22024112121434), we get a palindrome (65436233263456).
The spelling of 43412121142022 in words is "forty-three trillion, four hundred twelve billion, one hundred twenty-one million, one hundred forty-two thousand, twenty-two".
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