Base | Representation |
---|---|
bin | 1100101000100111011… |
… | …01001100110111110001 |
3 | 1112111112201201110222122 |
4 | 12110103231030313301 |
5 | 24103040303010301 |
6 | 531233311444025 |
7 | 43235645530463 |
oct | 6242355146761 |
9 | 1474481643878 |
10 | 434122313201 |
11 | 158123801345 |
12 | 70176826615 |
13 | 31c25a7b905 |
14 | 17023cc0133 |
15 | b45c3a881b |
hex | 6513b4cdf1 |
434122313201 has 2 divisors, whose sum is σ = 434122313202. Its totient is φ = 434122313200.
The previous prime is 434122313161. The next prime is 434122313221. The reversal of 434122313201 is 102313221434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 374574600625 + 59547712576 = 612025^2 + 244024^2 .
It is a cyclic number.
It is not a de Polignac number, because 434122313201 - 210 = 434122312177 is a prime.
It is not a weakly prime, because it can be changed into another prime (434122313221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217061156600 + 217061156601.
It is an arithmetic number, because the mean of its divisors is an integer number (217061156601).
Almost surely, 2434122313201 is an apocalyptic number.
It is an amenable number.
434122313201 is a deficient number, since it is larger than the sum of its proper divisors (1).
434122313201 is an equidigital number, since it uses as much as digits as its factorization.
434122313201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 434122313201 its reverse (102313221434), we get a palindrome (536435534635).
The spelling of 434122313201 in words is "four hundred thirty-four billion, one hundred twenty-two million, three hundred thirteen thousand, two hundred one".
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