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434122313221 is a prime number
BaseRepresentation
bin1100101000100111011…
…01001100111000000101
31112111112201201111000101
412110103231030320011
524103040303010341
6531233311444101
743235645530522
oct6242355147005
91474481644011
10434122313221
11158123801363
1270176826631
1331c25a7b91c
1417023cc0149
15b45c3a8831
hex6513b4ce05

434122313221 has 2 divisors, whose sum is σ = 434122313222. Its totient is φ = 434122313220.

The previous prime is 434122313201. The next prime is 434122313297. The reversal of 434122313221 is 122313221434.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 287156656900 + 146965656321 = 535870^2 + 383361^2 .

It is a cyclic number.

It is not a de Polignac number, because 434122313221 - 227 = 433988095493 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 434122313221.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434122313201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217061156610 + 217061156611.

It is an arithmetic number, because the mean of its divisors is an integer number (217061156611).

Almost surely, 2434122313221 is an apocalyptic number.

It is an amenable number.

434122313221 is a deficient number, since it is larger than the sum of its proper divisors (1).

434122313221 is an equidigital number, since it uses as much as digits as its factorization.

434122313221 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 28.

Adding to 434122313221 its reverse (122313221434), we get a palindrome (556435534655).

The spelling of 434122313221 in words is "four hundred thirty-four billion, one hundred twenty-two million, three hundred thirteen thousand, two hundred twenty-one".