434124011131 has 2 divisors, whose sum is σ = 434124011132. Its totient is φ = 434124011130.

The previous prime is 434124011117. The next prime is 434124011147. The reversal of 434124011131 is 131110421434.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 434124011131 - 2⁵ = 434124011099 is a prime.

It is a super-2 number, since 2×434124011131² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 434124011096 and 434124011105.

It is not a weakly prime, because it can be changed into another prime (434124611131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217062005565 + 217062005566.

It is an arithmetic number, because the mean of its divisors is an integer number (217062005566).

Almost surely, 2^434124011131 is an apocalyptic number.

434124011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

434124011131 is an equidigital number, since it uses as much as digits as its factorization.

434124011131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 434124011131 its reverse (131110421434), we get a palindrome (565234432565).

The spelling of 434124011131 in words is "four hundred thirty-four billion, one hundred twenty-four million, eleven thousand, one hundred thirty-one".