Base | Representation |
---|---|
bin | 111111001011001010011… |
… | …100011001110000010010 |
3 | 120101000200121002111212212 |
4 | 333023022130121300102 |
5 | 1032112002213141424 |
6 | 13122212152552122 |
7 | 625435536100220 |
oct | 77131234316022 |
9 | 16330617074785 |
10 | 4341313412114 |
11 | 1424160274968 |
12 | 5a14610b2642 |
13 | 2564cbb2c513 |
14 | 110199261b10 |
15 | 77dda5e010e |
hex | 3f2ca719c12 |
4341313412114 has 16 divisors (see below), whose sum is σ = 7643393498688. Its totient is φ = 1810277407152.
The previous prime is 4341313412099. The next prime is 4341313412119. The reversal of 4341313412114 is 4112143131434.
It is a happy number.
4341313412114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (4341313412119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4190456444 + ... + 4190457479.
It is an arithmetic number, because the mean of its divisors is an integer number (477712093668).
Almost surely, 24341313412114 is an apocalyptic number.
4341313412114 is a deficient number, since it is larger than the sum of its proper divisors (3302080086574).
4341313412114 is a wasteful number, since it uses less digits than its factorization.
4341313412114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8380913969.
The product of its digits is 13824, while the sum is 32.
Adding to 4341313412114 its reverse (4112143131434), we get a palindrome (8453456543548).
The spelling of 4341313412114 in words is "four trillion, three hundred forty-one billion, three hundred thirteen million, four hundred twelve thousand, one hundred fourteen".
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