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43413150242149 is a prime number
BaseRepresentation
bin10011101111011111010010…
…11001100001010101100101
312200201020221002021011200221
421313233221121201111211
521142240112430222044
6232155420443204341
712100332222315202
oct1167575131412545
9180636832234627
1043413150242149
1112918460595766
124a519142166b1
131b2bac4c8c86c
14aa12c9c4cca9
15504420587484
hex277be9661565

43413150242149 has 2 divisors, whose sum is σ = 43413150242150. Its totient is φ = 43413150242148.

The previous prime is 43413150242123. The next prime is 43413150242153. The reversal of 43413150242149 is 94124205131434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29906187509025 + 13506962733124 = 5468655^2 + 3675182^2 .

It is a cyclic number.

It is not a de Polignac number, because 43413150242149 - 211 = 43413150240101 is a prime.

It is a super-2 number, since 2×434131502421492 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43413150242249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21706575121074 + 21706575121075.

It is an arithmetic number, because the mean of its divisors is an integer number (21706575121075).

Almost surely, 243413150242149 is an apocalyptic number.

It is an amenable number.

43413150242149 is a deficient number, since it is larger than the sum of its proper divisors (1).

43413150242149 is an equidigital number, since it uses as much as digits as its factorization.

43413150242149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 43.

The spelling of 43413150242149 in words is "forty-three trillion, four hundred thirteen billion, one hundred fifty million, two hundred forty-two thousand, one hundred forty-nine".