Base | Representation |
---|---|
bin | 110001010110101110001110… |
… | …1111111001101010111111011 |
3 | 2002221010120021211122202000121 |
4 | 1202231130131333031113323 |
5 | 423400302304104441444 |
6 | 4135153131533314111 |
7 | 160304652223433641 |
oct | 14255343577152773 |
9 | 2087116254582017 |
10 | 434131502421499 |
11 | 116367155371a03 |
12 | 40835715935937 |
13 | 1583156a9b974c |
14 | 792c110b73191 |
15 | 352cb53a9d084 |
hex | 18ad71dfcd5fb |
434131502421499 has 2 divisors, whose sum is σ = 434131502421500. Its totient is φ = 434131502421498.
The previous prime is 434131502421467. The next prime is 434131502421583. The reversal of 434131502421499 is 994124205131434.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434131502421499 - 25 = 434131502421467 is a prime.
It is a super-2 number, since 2×4341315024214992 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (434131502481499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217065751210749 + 217065751210750.
It is an arithmetic number, because the mean of its divisors is an integer number (217065751210750).
Almost surely, 2434131502421499 is an apocalyptic number.
434131502421499 is a deficient number, since it is larger than the sum of its proper divisors (1).
434131502421499 is an equidigital number, since it uses as much as digits as its factorization.
434131502421499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 52.
The spelling of 434131502421499 in words is "four hundred thirty-four trillion, one hundred thirty-one billion, five hundred two million, four hundred twenty-one thousand, four hundred ninety-nine".
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