Base | Representation |
---|---|
bin | 110001010110110011100101… |
… | …1011110100100001100111111 |
3 | 2002221011122222100002102002201 |
4 | 1202231213023132210030333 |
5 | 423400444332234100211 |
6 | 4135202313043332331 |
7 | 160305540222145465 |
oct | 14255471336441477 |
9 | 2087148870072081 |
10 | 434143003034431 |
11 | 116371017145699 |
12 | 408379a53810a7 |
13 | 15832681552162 |
14 | 792c8c2318835 |
15 | 352d0c85770c1 |
hex | 18ad9cb7a433f |
434143003034431 has 2 divisors, whose sum is σ = 434143003034432. Its totient is φ = 434143003034430.
The previous prime is 434143003034423. The next prime is 434143003034473. The reversal of 434143003034431 is 134430300341434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434143003034431 - 23 = 434143003034423 is a prime.
It is a super-2 number, since 2×4341430030344312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434143003034401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217071501517215 + 217071501517216.
It is an arithmetic number, because the mean of its divisors is an integer number (217071501517216).
Almost surely, 2434143003034431 is an apocalyptic number.
434143003034431 is a deficient number, since it is larger than the sum of its proper divisors (1).
434143003034431 is an equidigital number, since it uses as much as digits as its factorization.
434143003034431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 434143003034431 its reverse (134430300341434), we get a palindrome (568573303375865).
The spelling of 434143003034431 in words is "four hundred thirty-four trillion, one hundred forty-three billion, three million, thirty-four thousand, four hundred thirty-one".
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