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43417483141 is a prime number
BaseRepresentation
bin101000011011111000…
…100011011110000101
311011001211122200001011
4220123320203132011
51202404333430031
631540135202221
73064632342334
oct503370433605
9134054580034
1043417483141
111746004577a
1284b8516371
13412c0ba036
14215c409d1b
1511e1a446b1
hexa1be23785

43417483141 has 2 divisors, whose sum is σ = 43417483142. Its totient is φ = 43417483140.

The previous prime is 43417483099. The next prime is 43417483261. The reversal of 43417483141 is 14138471434.

43417483141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22773828100 + 20643655041 = 150910^2 + 143679^2 .

It is a cyclic number.

It is not a de Polignac number, because 43417483141 - 29 = 43417482629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43417483094 and 43417483103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43417483541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21708741570 + 21708741571.

It is an arithmetic number, because the mean of its divisors is an integer number (21708741571).

Almost surely, 243417483141 is an apocalyptic number.

It is an amenable number.

43417483141 is a deficient number, since it is larger than the sum of its proper divisors (1).

43417483141 is an equidigital number, since it uses as much as digits as its factorization.

43417483141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129024, while the sum is 40.

The spelling of 43417483141 in words is "forty-three billion, four hundred seventeen million, four hundred eighty-three thousand, one hundred forty-one".