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434205444137 is a prime number
BaseRepresentation
bin1100101000110001010…
…10010100100000101001
31112111202112010222012012
412110120222110200221
524103223043203022
6531245441325305
743241005243643
oct6243052244051
91474675128165
10434205444137
111581667208a3
127019a636835
1331c3a06710a
1417030d5d893
15b464829de2
hex6518a94829

434205444137 has 2 divisors, whose sum is σ = 434205444138. Its totient is φ = 434205444136.

The previous prime is 434205444089. The next prime is 434205444139. The reversal of 434205444137 is 731444502434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 327028434496 + 107177009641 = 571864^2 + 327379^2 .

It is a cyclic number.

It is not a de Polignac number, because 434205444137 - 26 = 434205444073 is a prime.

Together with 434205444139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 434205444094 and 434205444103.

It is not a weakly prime, because it can be changed into another prime (434205444139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217102722068 + 217102722069.

It is an arithmetic number, because the mean of its divisors is an integer number (217102722069).

Almost surely, 2434205444137 is an apocalyptic number.

It is an amenable number.

434205444137 is a deficient number, since it is larger than the sum of its proper divisors (1).

434205444137 is an equidigital number, since it uses as much as digits as its factorization.

434205444137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 41.

The spelling of 434205444137 in words is "four hundred thirty-four billion, two hundred five million, four hundred forty-four thousand, one hundred thirty-seven".