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43421035326037 is a prime number
BaseRepresentation
bin10011101111101101111110…
…11000101110101001010101
312200202000021121102221022221
421313312333120232221111
521142402240020413122
6232203203120022341
712101031506400025
oct1167667730565125
9180660247387287
1043421035326037
1112920837503a16
124a53354a619b1
131b2c780768a85
14aa1837161a85
155047329336c7
hex277dbf62ea55

43421035326037 has 2 divisors, whose sum is σ = 43421035326038. Its totient is φ = 43421035326036.

The previous prime is 43421035326029. The next prime is 43421035326043. The reversal of 43421035326037 is 73062353012434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31737156013476 + 11683879312561 = 5633574^2 + 3418169^2 .

It is a cyclic number.

It is not a de Polignac number, because 43421035326037 - 23 = 43421035326029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43421035325984 and 43421035326002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43421035323037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21710517663018 + 21710517663019.

It is an arithmetic number, because the mean of its divisors is an integer number (21710517663019).

Almost surely, 243421035326037 is an apocalyptic number.

It is an amenable number.

43421035326037 is a deficient number, since it is larger than the sum of its proper divisors (1).

43421035326037 is an equidigital number, since it uses as much as digits as its factorization.

43421035326037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1088640, while the sum is 43.

The spelling of 43421035326037 in words is "forty-three trillion, four hundred twenty-one billion, thirty-five million, three hundred twenty-six thousand, thirty-seven".