Base | Representation |
---|---|
bin | 101000011100000111… |
… | …001100011110100111 |
3 | 11011002002212122202210 |
4 | 220130013030132213 |
5 | 1202411324234002 |
6 | 31540353334503 |
7 | 3065010065652 |
oct | 503407143647 |
9 | 134062778683 |
10 | 43421321127 |
11 | 17462227268 |
12 | 84b9867433 |
13 | 412cb31c32 |
14 | 215cb28899 |
15 | 11e205196c |
hex | a1c1cc7a7 |
43421321127 has 16 divisors (see below), whose sum is σ = 58733821440. Its totient is φ = 28531047552.
The previous prime is 43421321123. The next prime is 43421321143. The reversal of 43421321127 is 72112312434.
43421321127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 43421321127 - 22 = 43421321123 is a prime.
It is a super-2 number, since 2×434213211272 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43421321094 and 43421321103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43421321123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 297103 + ... + 418464.
It is an arithmetic number, because the mean of its divisors is an integer number (3670863840).
Almost surely, 243421321127 is an apocalyptic number.
43421321127 is a deficient number, since it is larger than the sum of its proper divisors (15312500313).
43421321127 is a wasteful number, since it uses less digits than its factorization.
43421321127 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 715862.
The product of its digits is 8064, while the sum is 30.
The spelling of 43421321127 in words is "forty-three billion, four hundred twenty-one million, three hundred twenty-one thousand, one hundred twenty-seven".
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