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43421321143 is a prime number
BaseRepresentation
bin101000011100000111…
…001100011110110111
311011002002212122210101
4220130013030132313
51202411324234033
631540353334531
73065010066004
oct503407143667
9134062778711
1043421321143
1117462227282
1284b9867447
13412cb31c45
14215cb288ab
1511e205197d
hexa1c1cc7b7

43421321143 has 2 divisors, whose sum is σ = 43421321144. Its totient is φ = 43421321142.

The previous prime is 43421321123. The next prime is 43421321147. The reversal of 43421321143 is 34112312434.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43421321143 - 213 = 43421312951 is a prime.

It is a super-3 number, since 3×434213211433 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43421321147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21710660571 + 21710660572.

It is an arithmetic number, because the mean of its divisors is an integer number (21710660572).

Almost surely, 243421321143 is an apocalyptic number.

43421321143 is a deficient number, since it is larger than the sum of its proper divisors (1).

43421321143 is an equidigital number, since it uses as much as digits as its factorization.

43421321143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 28.

Adding to 43421321143 its reverse (34112312434), we get a palindrome (77533633577).

The spelling of 43421321143 in words is "forty-three billion, four hundred twenty-one million, three hundred twenty-one thousand, one hundred forty-three".