Base | Representation |
---|---|
bin | 10011101111110000001011… |
… | …00010101100000110001001 |
3 | 12200202010022122012112220102 |
4 | 21313320011202230012021 |
5 | 21142412142324422103 |
6 | 232203520003335145 |
7 | 12101102621020631 |
oct | 1167700542540611 |
9 | 180663278175812 |
10 | 43422212342153 |
11 | 12921290941607 |
12 | 4a536230814b5 |
13 | 1b2c90a573908 |
14 | aa19095cb6c1 |
15 | 5047a0e2de88 |
hex | 277e058ac189 |
43422212342153 has 2 divisors, whose sum is σ = 43422212342154. Its totient is φ = 43422212342152.
The previous prime is 43422212342147. The next prime is 43422212342189. The reversal of 43422212342153 is 35124321222434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43186557435904 + 235654906249 = 6571648^2 + 485443^2 .
It is a cyclic number.
It is not a de Polignac number, because 43422212342153 - 24 = 43422212342137 is a prime.
It is not a weakly prime, because it can be changed into another prime (43422212342653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21711106171076 + 21711106171077.
It is an arithmetic number, because the mean of its divisors is an integer number (21711106171077).
Almost surely, 243422212342153 is an apocalyptic number.
It is an amenable number.
43422212342153 is a deficient number, since it is larger than the sum of its proper divisors (1).
43422212342153 is an equidigital number, since it uses as much as digits as its factorization.
43422212342153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 276480, while the sum is 38.
Adding to 43422212342153 its reverse (35124321222434), we get a palindrome (78546533564587).
The spelling of 43422212342153 in words is "forty-three trillion, four hundred twenty-two billion, two hundred twelve million, three hundred forty-two thousand, one hundred fifty-three".
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