Base | Representation |
---|---|
bin | 111111001100000111101… |
… | …000100111001111001011 |
3 | 120101010100010211202121021 |
4 | 333030013220213033023 |
5 | 1032121103021220433 |
6 | 13122502104453311 |
7 | 625503143123455 |
oct | 77140750471713 |
9 | 16333303752537 |
10 | 4342340023243 |
11 | 1424637814012 |
12 | 5a16a8a7a237 |
13 | 256633726021 |
14 | 1102557392d5 |
15 | 77e4a7cb22d |
hex | 3f307a273cb |
4342340023243 has 2 divisors, whose sum is σ = 4342340023244. Its totient is φ = 4342340023242.
The previous prime is 4342340023237. The next prime is 4342340023261. The reversal of 4342340023243 is 3423200432434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4342340023243 - 213 = 4342340015051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4342340023199 and 4342340023208.
It is not a weakly prime, because it can be changed into another prime (4342340023213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171170011621 + 2171170011622.
It is an arithmetic number, because the mean of its divisors is an integer number (2171170011622).
Almost surely, 24342340023243 is an apocalyptic number.
4342340023243 is a deficient number, since it is larger than the sum of its proper divisors (1).
4342340023243 is an equidigital number, since it uses as much as digits as its factorization.
4342340023243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 34.
Adding to 4342340023243 its reverse (3423200432434), we get a palindrome (7765540455677).
The spelling of 4342340023243 in words is "four trillion, three hundred forty-two billion, three hundred forty million, twenty-three thousand, two hundred forty-three".
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