Base | Representation |
---|---|
bin | 10011101111111111010100… |
… | …01011100001111101111001 |
3 | 12200202220022021212222222121 |
4 | 21313333222023201331321 |
5 | 21143030320331033423 |
6 | 232211342500321241 |
7 | 12101511251242252 |
oct | 1167775213417571 |
9 | 180686267788877 |
10 | 43430343221113 |
11 | 12924783581292 |
12 | 4a551120a3221 |
13 | 1b30604c4c5b4 |
14 | aa207b403b29 |
15 | 504ac9b7d45d |
hex | 277fea2e1f79 |
43430343221113 has 2 divisors, whose sum is σ = 43430343221114. Its totient is φ = 43430343221112.
The previous prime is 43430343221099. The next prime is 43430343221119. The reversal of 43430343221113 is 31112234303434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43356851806464 + 73491414649 = 6584592^2 + 271093^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43430343221113 is a prime.
It is not a weakly prime, because it can be changed into another prime (43430343221119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21715171610556 + 21715171610557.
It is an arithmetic number, because the mean of its divisors is an integer number (21715171610557).
Almost surely, 243430343221113 is an apocalyptic number.
It is an amenable number.
43430343221113 is a deficient number, since it is larger than the sum of its proper divisors (1).
43430343221113 is an equidigital number, since it uses as much as digits as its factorization.
43430343221113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 43430343221113 its reverse (31112234303434), we get a palindrome (74542577524547).
The spelling of 43430343221113 in words is "forty-three trillion, four hundred thirty billion, three hundred forty-three million, two hundred twenty-one thousand, one hundred thirteen".
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