43431011013433 has 8 divisors (see below), whose sum is σ = 45328235331456. Its totient is φ = 41534529986400.

The previous prime is 43431011013407. The next prime is 43431011013457. The reversal of 43431011013433 is 33431011013434.

It is a happy number.

43431011013433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 43431011013433 - 2⁴¹ = 41231987757881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43431011013395 and 43431011013404.

It is not an unprimeable number, because it can be changed into a prime (43431011013473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185703333 + ... + 185937058.

It is an arithmetic number, because the mean of its divisors is an integer number (5666029416432).

Almost surely, 2^{43431011013433} is an apocalyptic number.

It is an amenable number.

43431011013433 is a deficient number, since it is larger than the sum of its proper divisors (1897224318023).

43431011013433 is a wasteful number, since it uses less digits than its factorization.

43431011013433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371645495.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 43431011013433 its reverse (33431011013434), we get a palindrome (76862022026867).

Subtracting from 43431011013433 its reverse (33431011013434), we obtain a palindrome (9999999999999).

The spelling of 43431011013433 in words is "forty-three trillion, four hundred thirty-one billion, eleven million, thirteen thousand, four hundred thirty-three".