Base | Representation |
---|---|
bin | 10011110000000000100011… |
… | …11110111101001100011111 |
3 | 12200202222000211110100210112 |
4 | 21320000101332331030133 |
5 | 21143033202304412112 |
6 | 232211533033400235 |
7 | 12101533640341463 |
oct | 1170002176751437 |
9 | 180688024410715 |
10 | 43431011013407 |
11 | 12924a96522546 |
12 | 4a5527986907b |
13 | 1b306b03c2b74 |
14 | aa2101d964a3 |
15 | 504b185dca22 |
hex | 278011fbd31f |
43431011013407 has 2 divisors, whose sum is σ = 43431011013408. Its totient is φ = 43431011013406.
The previous prime is 43431011013373. The next prime is 43431011013457. The reversal of 43431011013407 is 70431011013434.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43431011013407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43431011013457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21715505506703 + 21715505506704.
It is an arithmetic number, because the mean of its divisors is an integer number (21715505506704).
Almost surely, 243431011013407 is an apocalyptic number.
43431011013407 is a deficient number, since it is larger than the sum of its proper divisors (1).
43431011013407 is an equidigital number, since it uses as much as digits as its factorization.
43431011013407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 43431011013407 in words is "forty-three trillion, four hundred thirty-one billion, eleven million, thirteen thousand, four hundred seven".
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