Base | Representation |
---|---|
bin | 10011110000000000100011… |
… | …11110111101001101010001 |
3 | 12200202222000211110100212101 |
4 | 21320000101332331031101 |
5 | 21143033202304412312 |
6 | 232211533033400401 |
7 | 12101533640341564 |
oct | 1170002176751521 |
9 | 180688024410771 |
10 | 43431011013457 |
11 | 12924a96522591 |
12 | 4a55279869101 |
13 | 1b306b03c2bb2 |
14 | aa2101d964db |
15 | 504b185dca57 |
hex | 278011fbd351 |
43431011013457 has 2 divisors, whose sum is σ = 43431011013458. Its totient is φ = 43431011013456.
The previous prime is 43431011013407. The next prime is 43431011013473. The reversal of 43431011013457 is 75431011013434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31279400654401 + 12151610359056 = 5592799^2 + 3485916^2 .
It is a cyclic number.
It is not a de Polignac number, because 43431011013457 - 231 = 43428863529809 is a prime.
It is not a weakly prime, because it can be changed into another prime (43431011013407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21715505506728 + 21715505506729.
It is an arithmetic number, because the mean of its divisors is an integer number (21715505506729).
Almost surely, 243431011013457 is an apocalyptic number.
It is an amenable number.
43431011013457 is a deficient number, since it is larger than the sum of its proper divisors (1).
43431011013457 is an equidigital number, since it uses as much as digits as its factorization.
43431011013457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
The spelling of 43431011013457 in words is "forty-three trillion, four hundred thirty-one billion, eleven million, thirteen thousand, four hundred fifty-seven".
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