Base | Representation |
---|---|
bin | 11001111000110… |
… | …000101111110011 |
3 | 1010021020020111102 |
4 | 121320300233303 |
5 | 1342140411011 |
6 | 111032435015 |
7 | 13522401203 |
oct | 3170605763 |
9 | 1107206442 |
10 | 434310131 |
11 | 20317a6a2 |
12 | 101548a6b |
13 | 6bc95358 |
14 | 41976403 |
15 | 281de73b |
hex | 19e30bf3 |
434310131 has 2 divisors, whose sum is σ = 434310132. Its totient is φ = 434310130.
The previous prime is 434310073. The next prime is 434310133. The reversal of 434310131 is 131013434.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434310131 is a prime.
It is a super-2 number, since 2×4343101312 = 377250579778474322, which contains 22 as substring.
Together with 434310133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (434310133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217155065 + 217155066.
It is an arithmetic number, because the mean of its divisors is an integer number (217155066).
Almost surely, 2434310131 is an apocalyptic number.
434310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
434310131 is an equidigital number, since it uses as much as digits as its factorization.
434310131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
The square root of 434310131 is about 20840.1087089295. The cubic root of 434310131 is about 757.2977271105.
Adding to 434310131 its reverse (131013434), we get a palindrome (565323565).
The spelling of 434310131 in words is "four hundred thirty-four million, three hundred ten thousand, one hundred thirty-one".
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