Base | Representation |
---|---|
bin | 1100101001000000010… |
… | …01011001011011001001 |
3 | 1112112002021110110022102 |
4 | 12110200021121123021 |
5 | 24104002220444431 |
6 | 531310125203145 |
7 | 43244061565052 |
oct | 6244011313311 |
9 | 1475067413272 |
10 | 434331031241 |
11 | 1582205a9298 |
12 | 702147004b5 |
13 | 31c5a099103 |
14 | 170438d1729 |
15 | b470885dcb |
hex | 65202596c9 |
434331031241 has 2 divisors, whose sum is σ = 434331031242. Its totient is φ = 434331031240.
The previous prime is 434331031229. The next prime is 434331031249. The reversal of 434331031241 is 142130133434.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 427710768016 + 6620263225 = 653996^2 + 81365^2 .
It is a cyclic number.
It is not a de Polignac number, because 434331031241 - 214 = 434331014857 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (434331031249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217165515620 + 217165515621.
It is an arithmetic number, because the mean of its divisors is an integer number (217165515621).
Almost surely, 2434331031241 is an apocalyptic number.
It is an amenable number.
434331031241 is a deficient number, since it is larger than the sum of its proper divisors (1).
434331031241 is an equidigital number, since it uses as much as digits as its factorization.
434331031241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 434331031241 its reverse (142130133434), we get a palindrome (576461164675).
The spelling of 434331031241 in words is "four hundred thirty-four billion, three hundred thirty-one million, thirty-one thousand, two hundred forty-one".
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