Base | Representation |
---|---|
bin | 1000000101110000… |
… | …11010111100000011 |
3 | 102012200201010011021 |
4 | 10002320122330003 |
5 | 32343341442011 |
6 | 1554552130311 |
7 | 212426354404 |
oct | 40270327403 |
9 | 12180633137 |
10 | 4343312131 |
11 | 1929760764 |
12 | a12696997 |
13 | 542aa57a2 |
14 | 2d2b9d9ab |
15 | 1a648c471 |
hex | 102e1af03 |
4343312131 has 2 divisors, whose sum is σ = 4343312132. Its totient is φ = 4343312130.
The previous prime is 4343312123. The next prime is 4343312147. The reversal of 4343312131 is 1312133434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4343312131 - 23 = 4343312123 is a prime.
It is a super-2 number, since 2×43433121312 = 37728720534583522322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4343312096 and 4343312105.
It is not a weakly prime, because it can be changed into another prime (4343312101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171656065 + 2171656066.
It is an arithmetic number, because the mean of its divisors is an integer number (2171656066).
Almost surely, 24343312131 is an apocalyptic number.
4343312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4343312131 is an equidigital number, since it uses as much as digits as its factorization.
4343312131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 25.
The square root of 4343312131 is about 65903.8096850250. The cubic root of 4343312131 is about 1631.5748928561.
Adding to 4343312131 its reverse (1312133434), we get a palindrome (5655445565).
The spelling of 4343312131 in words is "four billion, three hundred forty-three million, three hundred twelve thousand, one hundred thirty-one".
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