Base | Representation |
---|---|
bin | 10011110000000111000110… |
… | …01100111011010110011011 |
3 | 12200210022002110022221121121 |
4 | 21320003203030323112123 |
5 | 21143112344401122021 |
6 | 232213313223150111 |
7 | 12102016631610106 |
oct | 1170034314732633 |
9 | 180708073287547 |
10 | 43434521114011 |
11 | 12926527919035 |
12 | 4a55a992a5337 |
13 | 1b30b1c687a81 |
14 | aa235622373d |
15 | 504c71842741 |
hex | 2780e333b59b |
43434521114011 has 2 divisors, whose sum is σ = 43434521114012. Its totient is φ = 43434521114010.
The previous prime is 43434521113967. The next prime is 43434521114099. The reversal of 43434521114011 is 11041112543434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43434521114011 - 29 = 43434521113499 is a prime.
It is not a weakly prime, because it can be changed into another prime (43434521114911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21717260557005 + 21717260557006.
It is an arithmetic number, because the mean of its divisors is an integer number (21717260557006).
Almost surely, 243434521114011 is an apocalyptic number.
43434521114011 is a deficient number, since it is larger than the sum of its proper divisors (1).
43434521114011 is an equidigital number, since it uses as much as digits as its factorization.
43434521114011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 43434521114011 its reverse (11041112543434), we get a palindrome (54475633657445).
The spelling of 43434521114011 in words is "forty-three trillion, four hundred thirty-four billion, five hundred twenty-one million, one hundred fourteen thousand, eleven".
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