Base | Representation |
---|---|
bin | 1100101001001100000… |
… | …11010100011000110001 |
3 | 1112112100011212201112021 |
4 | 12110212003110120301 |
5 | 24104203101213131 |
6 | 531324024431441 |
7 | 43246403634226 |
oct | 6244603243061 |
9 | 1475304781467 |
10 | 434430101041 |
11 | 158271514962 |
12 | 70241918581 |
13 | 31c747753b1 |
14 | 17052b1d94d |
15 | b479404e11 |
hex | 65260d4631 |
434430101041 has 2 divisors, whose sum is σ = 434430101042. Its totient is φ = 434430101040.
The previous prime is 434430101023. The next prime is 434430101051. The reversal of 434430101041 is 140101034434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 336395360016 + 98034741025 = 579996^2 + 313105^2 .
It is a cyclic number.
It is not a de Polignac number, because 434430101041 - 213 = 434430092849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 434430100997 and 434430101015.
It is not a weakly prime, because it can be changed into another prime (434430101011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217215050520 + 217215050521.
It is an arithmetic number, because the mean of its divisors is an integer number (217215050521).
Almost surely, 2434430101041 is an apocalyptic number.
It is an amenable number.
434430101041 is a deficient number, since it is larger than the sum of its proper divisors (1).
434430101041 is an equidigital number, since it uses as much as digits as its factorization.
434430101041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 434430101041 its reverse (140101034434), we get a palindrome (574531135475).
The spelling of 434430101041 in words is "four hundred thirty-four billion, four hundred thirty million, one hundred one thousand, forty-one".
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