Base | Representation |
---|---|
bin | 10011110000101100001010… |
… | …10010010111111110000100 |
3 | 12200212012110021012100122201 |
4 | 21320112011102113332010 |
5 | 21143424123100221012 |
6 | 232230403552204244 |
7 | 12103323021224233 |
oct | 1170260522277604 |
9 | 180765407170581 |
10 | 43454420320132 |
11 | 12933a09464128 |
12 | 4a59911539684 |
13 | 1b32971201753 |
14 | aa32c2d8cb1a |
15 | 5055387ed857 |
hex | 278585497f84 |
43454420320132 has 24 divisors (see below), whose sum is σ = 78114344142464. Its totient is φ = 21136244278752.
The previous prime is 43454420320123. The next prime is 43454420320133. The reversal of 43454420320132 is 23102302445434.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a junction number, because it is equal to n+sod(n) for n = 43454420320091 and 43454420320100.
It is not an unprimeable number, because it can be changed into a prime (43454420320133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25161318 + ... + 26832829.
Almost surely, 243454420320132 is an apocalyptic number.
It is an amenable number.
43454420320132 is a deficient number, since it is larger than the sum of its proper divisors (34659923822332).
43454420320132 is a wasteful number, since it uses less digits than its factorization.
43454420320132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51999835 (or 51999833 counting only the distinct ones).
The product of its (nonzero) digits is 276480, while the sum is 37.
Adding to 43454420320132 its reverse (23102302445434), we get a palindrome (66556722765566).
The spelling of 43454420320132 in words is "forty-three trillion, four hundred fifty-four billion, four hundred twenty million, three hundred twenty thousand, one hundred thirty-two".
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