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4350114149401 is a prime number
BaseRepresentation
bin111111010011010111000…
…000100011010000011001
3120101212101221020021211201
4333103113000203100121
51032233013210240101
613130225335154201
7626166612114346
oct77232700432031
916355357207751
104350114149401
111427967037069
125a30b8515961
132572a2222c87
141107920077cd
157825305ae01
hex3f4d7023419

4350114149401 has 2 divisors, whose sum is σ = 4350114149402. Its totient is φ = 4350114149400.

The previous prime is 4350114149399. The next prime is 4350114149417. The reversal of 4350114149401 is 1049414110534.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2278587231001 + 2071526918400 = 1509499^2 + 1439280^2 .

It is a cyclic number.

It is not a de Polignac number, because 4350114149401 - 21 = 4350114149399 is a prime.

It is a super-2 number, since 2×43501141494012 (a number of 26 digits) contains 22 as substring.

Together with 4350114149399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (4350114149471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175057074700 + 2175057074701.

It is an arithmetic number, because the mean of its divisors is an integer number (2175057074701).

Almost surely, 24350114149401 is an apocalyptic number.

It is an amenable number.

4350114149401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4350114149401 is an equidigital number, since it uses as much as digits as its factorization.

4350114149401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 37.

Adding to 4350114149401 its reverse (1049414110534), we get a palindrome (5399528259935).

The spelling of 4350114149401 in words is "four trillion, three hundred fifty billion, one hundred fourteen million, one hundred forty-nine thousand, four hundred one".