Base | Representation |
---|---|
bin | 111111010100010011000… |
… | …010001100111010100110 |
3 | 120101222000010012112022212 |
4 | 333110103002030322212 |
5 | 1032242044012341032 |
6 | 13130513312123422 |
7 | 626233561044152 |
oct | 77242302147246 |
9 | 16358003175285 |
10 | 4351121215142 |
11 | 14283335464a9 |
12 | 5a3339836572 |
13 | 257402a65270 |
14 | 110849a74062 |
15 | 782b1685bb2 |
hex | 3f51308cea6 |
4351121215142 has 8 divisors (see below), whose sum is σ = 7028734270656. Its totient is φ = 2008209791592.
The previous prime is 4351121215121. The next prime is 4351121215169. The reversal of 4351121215142 is 2415121211534.
4351121215142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 4351121215099 and 4351121215108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83675407958 + ... + 83675408009.
It is an arithmetic number, because the mean of its divisors is an integer number (878591783832).
Almost surely, 24351121215142 is an apocalyptic number.
4351121215142 is a deficient number, since it is larger than the sum of its proper divisors (2677613055514).
4351121215142 is a wasteful number, since it uses less digits than its factorization.
4351121215142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167350815982.
The product of its digits is 9600, while the sum is 32.
Adding to 4351121215142 its reverse (2415121211534), we get a palindrome (6766242426676).
The spelling of 4351121215142 in words is "four trillion, three hundred fifty-one billion, one hundred twenty-one million, two hundred fifteen thousand, one hundred forty-two".
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