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4351145901413 is a prime number
BaseRepresentation
bin111111010100010100100…
…000010111110101100101
3120101222001211122201112012
4333110110200113311211
51032242121322321123
613130515553204005
7626234310631613
oct77242440276545
916358054581465
104351145901413
111428346477683
125a3345b60605
13257407bc971c
1411084d05c6b3
15782b3910378
hex3f514817d65

4351145901413 has 2 divisors, whose sum is σ = 4351145901414. Its totient is φ = 4351145901412.

The previous prime is 4351145901391. The next prime is 4351145901499. The reversal of 4351145901413 is 3141095411534.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3910909670404 + 440236231009 = 1977602^2 + 663503^2 .

It is a cyclic number.

It is not a de Polignac number, because 4351145901413 - 212 = 4351145897317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4351145906413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175572950706 + 2175572950707.

It is an arithmetic number, because the mean of its divisors is an integer number (2175572950707).

Almost surely, 24351145901413 is an apocalyptic number.

It is an amenable number.

4351145901413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4351145901413 is an equidigital number, since it uses as much as digits as its factorization.

4351145901413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 4351145901413 in words is "four trillion, three hundred fifty-one billion, one hundred forty-five million, nine hundred one thousand, four hundred thirteen".