Search a number
-
+
4351223140213 is a prime number
BaseRepresentation
bin111111010100011001000…
…111000000111101110101
3120101222021012222212020111
4333110121013000331311
51032242301110441323
613130531352503021
7626236236304615
oct77243107007565
916358235885214
104351223140213
1114283860322a4
125a33679aaa71
1325741ac01061
14110859406a45
15782ba5bac0d
hex3f5191c0f75

4351223140213 has 2 divisors, whose sum is σ = 4351223140214. Its totient is φ = 4351223140212.

The previous prime is 4351223140169. The next prime is 4351223140249. The reversal of 4351223140213 is 3120413221534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4283811249169 + 67411891044 = 2069737^2 + 259638^2 .

It is a cyclic number.

It is not a de Polignac number, because 4351223140213 - 213 = 4351223132021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4351223140283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175611570106 + 2175611570107.

It is an arithmetic number, because the mean of its divisors is an integer number (2175611570107).

Almost surely, 24351223140213 is an apocalyptic number.

It is an amenable number.

4351223140213 is a deficient number, since it is larger than the sum of its proper divisors (1).

4351223140213 is an equidigital number, since it uses as much as digits as its factorization.

4351223140213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 4351223140213 its reverse (3120413221534), we get a palindrome (7471636361747).

The spelling of 4351223140213 in words is "four trillion, three hundred fifty-one billion, two hundred twenty-three million, one hundred forty thousand, two hundred thirteen".