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4352113200341 is a prime number
BaseRepresentation
bin111111010101001110001…
…010010100110011010101
3120102001120020210121012102
4333111032022110303111
51032301111434402331
613131155545531445
7626300264554244
oct77251612246325
916361506717172
104352113200341
1114287a2495685
125a3575aa3b85
1325753042735a
141109016d695b
157831d7d24cb
hex3f54e294cd5

4352113200341 has 2 divisors, whose sum is σ = 4352113200342. Its totient is φ = 4352113200340.

The previous prime is 4352113200319. The next prime is 4352113200511. The reversal of 4352113200341 is 1430023112534.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4275755484100 + 76357716241 = 2067790^2 + 276329^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4352113200341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4352113280341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2176056600170 + 2176056600171.

It is an arithmetic number, because the mean of its divisors is an integer number (2176056600171).

Almost surely, 24352113200341 is an apocalyptic number.

It is an amenable number.

4352113200341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4352113200341 is an equidigital number, since it uses as much as digits as its factorization.

4352113200341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 4352113200341 its reverse (1430023112534), we get a palindrome (5782136312875).

The spelling of 4352113200341 in words is "four trillion, three hundred fifty-two billion, one hundred thirteen million, two hundred thousand, three hundred forty-one".