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4353142311053 is a prime number
BaseRepresentation
bin111111010110001011100…
…000000100100010001101
3120102011012222020211200222
4333112023200010202031
51032310213412423203
613131450031201125
7626334632061104
oct77261340044215
916364188224628
104353142311053
1114291803917a8
125a38026761a5
132576656b77c3
1411099c26103b
157837dd14038
hex3f58b80488d

4353142311053 has 2 divisors, whose sum is σ = 4353142311054. Its totient is φ = 4353142311052.

The previous prime is 4353142311031. The next prime is 4353142311061. The reversal of 4353142311053 is 3501132413534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4352322233284 + 820077769 = 2086222^2 + 28637^2 .

It is a cyclic number.

It is not a de Polignac number, because 4353142311053 - 222 = 4353138116749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4353142311013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2176571155526 + 2176571155527.

It is an arithmetic number, because the mean of its divisors is an integer number (2176571155527).

Almost surely, 24353142311053 is an apocalyptic number.

It is an amenable number.

4353142311053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4353142311053 is an equidigital number, since it uses as much as digits as its factorization.

4353142311053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 4353142311053 its reverse (3501132413534), we get a palindrome (7854274724587).

The spelling of 4353142311053 in words is "four trillion, three hundred fifty-three billion, one hundred forty-two million, three hundred eleven thousand, fifty-three".