Base | Representation |
---|---|
bin | 111111010110001011101… |
… | …000000011000001010001 |
3 | 120102011020010012001221111 |
4 | 333112023220003001101 |
5 | 1032310214431331001 |
6 | 13131450144053321 |
7 | 626334655620133 |
oct | 77261350030121 |
9 | 16364203161844 |
10 | 4353144402001 |
11 | 142918158a75a |
12 | 5a3803304241 |
13 | 257665c6a455 |
14 | 11099c647053 |
15 | 7837e0c8851 |
hex | 3f58ba03051 |
4353144402001 has 2 divisors, whose sum is σ = 4353144402002. Its totient is φ = 4353144402000.
The previous prime is 4353144401941. The next prime is 4353144402017. The reversal of 4353144402001 is 1002044413534.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2673800550976 + 1679343851025 = 1635176^2 + 1295895^2 .
It is a cyclic number.
It is not a de Polignac number, because 4353144402001 - 231 = 4350996918353 is a prime.
It is not a weakly prime, because it can be changed into another prime (4353144402601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2176572201000 + 2176572201001.
It is an arithmetic number, because the mean of its divisors is an integer number (2176572201001).
Almost surely, 24353144402001 is an apocalyptic number.
It is an amenable number.
4353144402001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4353144402001 is an equidigital number, since it uses as much as digits as its factorization.
4353144402001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 4353144402001 its reverse (1002044413534), we get a palindrome (5355188815535).
The spelling of 4353144402001 in words is "four trillion, three hundred fifty-three billion, one hundred forty-four million, four hundred two thousand, one".
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