Search a number
-
+
43542131 is a prime number
BaseRepresentation
bin1010011000011…
…0011001110011
310000221011120112
42212012121303
542121322011
64153131535
71036046663
oct246063163
9100834515
1043542131
112263a936
12126b9bab
139036b99
145ad61a3
153c5158b
hex2986673

43542131 has 2 divisors, whose sum is σ = 43542132. Its totient is φ = 43542130.

The previous prime is 43542089. The next prime is 43542133. The reversal of 43542131 is 13124534.

43542131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43542131 - 210 = 43541107 is a prime.

It is a super-2 number, since 2×435421312 = 3791834344042322, which contains 22 as substring.

Together with 43542133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43542097 and 43542106.

It is not a weakly prime, because it can be changed into another prime (43542133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21771065 + 21771066.

It is an arithmetic number, because the mean of its divisors is an integer number (21771066).

Almost surely, 243542131 is an apocalyptic number.

43542131 is a deficient number, since it is larger than the sum of its proper divisors (1).

43542131 is an equidigital number, since it uses as much as digits as its factorization.

43542131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 23.

The square root of 43542131 is about 6598.6461490218. The cubic root of 43542131 is about 351.8059875888.

Adding to 43542131 its reverse (13124534), we get a palindrome (56666665).

The spelling of 43542131 in words is "forty-three million, five hundred forty-two thousand, one hundred thirty-one".