4365135141011 has 2 divisors, whose sum is σ = 4365135141012. Its totient is φ = 4365135141010.

The previous prime is 4365135140999. The next prime is 4365135141013. The reversal of 4365135141011 is 1101415315634.

4365135141011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4365135141011 - 2¹⁰ = 4365135139987 is a prime.

Together with 4365135141013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4365135141013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2182567570505 + 2182567570506.

It is an arithmetic number, because the mean of its divisors is an integer number (2182567570506).

Almost surely, 2^{4365135141011} is an apocalyptic number.

4365135141011 is a deficient number, since it is larger than the sum of its proper divisors (1).

4365135141011 is an equidigital number, since it uses as much as digits as its factorization.

4365135141011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 4365135141011 in words is "four trillion, three hundred sixty-five billion, one hundred thirty-five million, one hundred forty-one thousand, eleven".