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43907954653 is a prime number
BaseRepresentation
bin101000111001000111…
…100011011111011101
311012100000120012110201
4220321013203133131
51204410414022103
632100535503501
73113036312413
oct507107433735
9135300505421
1043907954653
1117691994232
128614827b91
1341a98b7074
1421a76012b3
15121eb2951d
hexa391e37dd

43907954653 has 2 divisors, whose sum is σ = 43907954654. Its totient is φ = 43907954652.

The previous prime is 43907954627. The next prime is 43907954693. The reversal of 43907954653 is 35645970934.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43286050809 + 621903844 = 208053^2 + 24938^2 .

It is a cyclic number.

It is not a de Polignac number, because 43907954653 - 25 = 43907954621 is a prime.

It is a super-3 number, since 3×439079546533 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43907954594 and 43907954603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43907954693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21953977326 + 21953977327.

It is an arithmetic number, because the mean of its divisors is an integer number (21953977327).

Almost surely, 243907954653 is an apocalyptic number.

It is an amenable number.

43907954653 is a deficient number, since it is larger than the sum of its proper divisors (1).

43907954653 is an equidigital number, since it uses as much as digits as its factorization.

43907954653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12247200, while the sum is 55.

The spelling of 43907954653 in words is "forty-three billion, nine hundred seven million, nine hundred fifty-four thousand, six hundred fifty-three".