Base | Representation |
---|---|
bin | 1100110010000100000… |
… | …00010001011001001011 |
3 | 1112222122012001110211012 |
4 | 12121002000101121023 |
5 | 24143432133003231 |
6 | 533432444154135 |
7 | 43505431446662 |
oct | 6310200213113 |
9 | 1488565043735 |
10 | 439194031691 |
11 | 15a296643528 |
12 | 7115123894b |
13 | 3255372b27c |
14 | 173856cddd9 |
15 | b657779e2b |
hex | 664201164b |
439194031691 has 2 divisors, whose sum is σ = 439194031692. Its totient is φ = 439194031690.
The previous prime is 439194031681. The next prime is 439194031693. The reversal of 439194031691 is 196130491934.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-439194031691 is a prime.
It is a super-2 number, since 2×4391940316912 (a number of 24 digits) contains 22 as substring.
Together with 439194031693, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (439194031693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 219597015845 + 219597015846.
It is an arithmetic number, because the mean of its divisors is an integer number (219597015846).
Almost surely, 2439194031691 is an apocalyptic number.
439194031691 is a deficient number, since it is larger than the sum of its proper divisors (1).
439194031691 is an equidigital number, since it uses as much as digits as its factorization.
439194031691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 50.
The spelling of 439194031691 in words is "four hundred thirty-nine billion, one hundred ninety-four million, thirty-one thousand, six hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •