Base | Representation |
---|---|
bin | 101000111010101001… |
… | …101001011100001101 |
3 | 11012101210221122002212 |
4 | 220322221221130031 |
5 | 1204434004403013 |
6 | 32103255000205 |
7 | 3113501011634 |
oct | 507251513415 |
9 | 135353848085 |
10 | 43933669133 |
11 | 176a5457972 |
12 | 8621369065 |
13 | 41b201b533 |
14 | 21aabb651b |
15 | 12220086a8 |
hex | a3aa6970d |
43933669133 has 2 divisors, whose sum is σ = 43933669134. Its totient is φ = 43933669132.
The previous prime is 43933669097. The next prime is 43933669139. The reversal of 43933669133 is 33196633934.
43933669133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28117588489 + 15816080644 = 167683^2 + 125762^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43933669133 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43933669139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21966834566 + 21966834567.
It is an arithmetic number, because the mean of its divisors is an integer number (21966834567).
Almost surely, 243933669133 is an apocalyptic number.
It is an amenable number.
43933669133 is a deficient number, since it is larger than the sum of its proper divisors (1).
43933669133 is an equidigital number, since it uses as much as digits as its factorization.
43933669133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2834352, while the sum is 50.
The spelling of 43933669133 in words is "forty-three billion, nine hundred thirty-three million, six hundred sixty-nine thousand, one hundred thirty-three".
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