Base | Representation |
---|---|
bin | 101000111110101100… |
… | …111110010110000011 |
3 | 11012120112212102101122 |
4 | 220332230332112003 |
5 | 1210103410300201 |
6 | 32114124022455 |
7 | 3115254566012 |
oct | 507654762603 |
9 | 135515772348 |
10 | 44001650051 |
11 | 1772a869a47 |
12 | 8640091a2b |
13 | 41c3131028 |
14 | 21b5c30a79 |
15 | 1227e85e1b |
hex | a3eb3e583 |
44001650051 has 2 divisors, whose sum is σ = 44001650052. Its totient is φ = 44001650050.
The previous prime is 44001650047. The next prime is 44001650053. The reversal of 44001650051 is 15005610044.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44001650051 - 22 = 44001650047 is a prime.
It is a super-2 number, since 2×440016500512 (a number of 22 digits) contains 22 as substring.
Together with 44001650053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 44001650051.
It is not a weakly prime, because it can be changed into another prime (44001650053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22000825025 + 22000825026.
It is an arithmetic number, because the mean of its divisors is an integer number (22000825026).
Almost surely, 244001650051 is an apocalyptic number.
44001650051 is a deficient number, since it is larger than the sum of its proper divisors (1).
44001650051 is an equidigital number, since it uses as much as digits as its factorization.
44001650051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 26.
The spelling of 44001650051 in words is "forty-four billion, one million, six hundred fifty thousand, fifty-one".
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