Base | Representation |
---|---|
bin | 100000000001000011100… |
… | …0000000010001010000111 |
3 | 120120122222021022001220202 |
4 | 1000002013000002022013 |
5 | 1034043314212202403 |
6 | 13205250345321115 |
7 | 632624551066331 |
oct | 100020700021207 |
9 | 16518867261822 |
10 | 4400311444103 |
11 | 1447186104593 |
12 | 5b098749619b |
13 | 25bc41b10813 |
14 | 112d94a14451 |
15 | 796dedc3688 |
hex | 40087002287 |
4400311444103 has 2 divisors, whose sum is σ = 4400311444104. Its totient is φ = 4400311444102.
The previous prime is 4400311444013. The next prime is 4400311444253. The reversal of 4400311444103 is 3014441130044.
Together with previous prime (4400311444013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4400311444103 - 234 = 4383131574919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4400311404103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2200155722051 + 2200155722052.
It is an arithmetic number, because the mean of its divisors is an integer number (2200155722052).
Almost surely, 24400311444103 is an apocalyptic number.
4400311444103 is a deficient number, since it is larger than the sum of its proper divisors (1).
4400311444103 is an equidigital number, since it uses as much as digits as its factorization.
4400311444103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4400311444103 its reverse (3014441130044), we get a palindrome (7414752574147).
The spelling of 4400311444103 in words is "four trillion, four hundred billion, three hundred eleven million, four hundred forty-four thousand, one hundred three".
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