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44012058113 is a prime number
BaseRepresentation
bin101000111111010100…
…101011011000000001
311012121021110012120102
4220333110223120001
51210114041324423
632115135052145
73115442215142
oct507724533001
9135537405512
1044012058113
1117735728751
128643671055
1341c533654a
1421b737dac9
151228d3ec28
hexa3f52b601

44012058113 has 2 divisors, whose sum is σ = 44012058114. Its totient is φ = 44012058112.

The previous prime is 44012058107. The next prime is 44012058119. The reversal of 44012058113 is 31185021044.

It is a balanced prime because it is at equal distance from previous prime (44012058107) and next prime (44012058119).

It can be written as a sum of positive squares in only one way, i.e., 43393889344 + 618168769 = 208312^2 + 24863^2 .

It is a cyclic number.

It is not a de Polignac number, because 44012058113 - 28 = 44012057857 is a prime.

It is a super-2 number, since 2×440120581132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (44012058119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22006029056 + 22006029057.

It is an arithmetic number, because the mean of its divisors is an integer number (22006029057).

Almost surely, 244012058113 is an apocalyptic number.

It is an amenable number.

44012058113 is a deficient number, since it is larger than the sum of its proper divisors (1).

44012058113 is an equidigital number, since it uses as much as digits as its factorization.

44012058113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 44012058113 its reverse (31185021044), we get a palindrome (75197079157).

The spelling of 44012058113 in words is "forty-four billion, twelve million, fifty-eight thousand, one hundred thirteen".