Base | Representation |
---|---|
bin | 100000000001011111100… |
… | …0101101010000011101111 |
3 | 120120202101211221201211201 |
4 | 1000002333011222003233 |
5 | 1034102231111123401 |
6 | 13205524002230331 |
7 | 632660065331422 |
oct | 100027705520357 |
9 | 16522354851751 |
10 | 4401252442351 |
11 | 1447619299496 |
12 | 5b0baa6553a7 |
13 | 25c061a6020b |
14 | 1130439a39b9 |
15 | 797477ecb01 |
hex | 400bf16a0ef |
4401252442351 has 2 divisors, whose sum is σ = 4401252442352. Its totient is φ = 4401252442350.
The previous prime is 4401252442339. The next prime is 4401252442397. The reversal of 4401252442351 is 1532442521044.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4401252442351 - 221 = 4401250345199 is a prime.
It is a super-2 number, since 2×44012524423512 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4401252442351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4401252442451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2200626221175 + 2200626221176.
It is an arithmetic number, because the mean of its divisors is an integer number (2200626221176).
Almost surely, 24401252442351 is an apocalyptic number.
4401252442351 is a deficient number, since it is larger than the sum of its proper divisors (1).
4401252442351 is an equidigital number, since it uses as much as digits as its factorization.
4401252442351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 4401252442351 its reverse (1532442521044), we get a palindrome (5933694963395).
The spelling of 4401252442351 in words is "four trillion, four hundred one billion, two hundred fifty-two million, four hundred forty-two thousand, three hundred fifty-one".
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