44013130001 has 2 divisors, whose sum is σ = 44013130002. Its totient is φ = 44013130000.

The previous prime is 44013129991. The next prime is 44013130003. The reversal of 44013130001 is 10003131044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29096171776 + 14916958225 = 170576^2 + 122135^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-44013130001 is a prime.

It is a super-2 number, since 2×44013130001² (a number of 22 digits) contains 22 as substring.

Together with 44013130003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (44013130003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22006565000 + 22006565001.

It is an arithmetic number, because the mean of its divisors is an integer number (22006565001).

Almost surely, 2^44013130001 is an apocalyptic number.

It is an amenable number.

44013130001 is a deficient number, since it is larger than the sum of its proper divisors (1).

44013130001 is an equidigital number, since it uses as much as digits as its factorization.

44013130001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 44013130001 its reverse (10003131044), we get a palindrome (54016261045).

The spelling of 44013130001 in words is "forty-four billion, thirteen million, one hundred thirty thousand, one".