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44013130037 is a prime number
BaseRepresentation
bin101000111111011000…
…110001000100110101
311012121100110122222022
4220333120301010311
51210114330130122
632115214042525
73115454301242
oct507730610465
9135540418868
1044013130037
11177362a0038
128643aa9445
1341c5620416
1421b757c5c9
151228ea2642
hexa3f631135

44013130037 has 2 divisors, whose sum is σ = 44013130038. Its totient is φ = 44013130036.

The previous prime is 44013130003. The next prime is 44013130069. The reversal of 44013130037 is 73003131044.

44013130037 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35094027556 + 8919102481 = 187334^2 + 94441^2 .

It is a cyclic number.

It is not a de Polignac number, because 44013130037 - 28 = 44013129781 is a prime.

It is a super-3 number, since 3×440131300373 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44013129988 and 44013130015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44013130087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22006565018 + 22006565019.

It is an arithmetic number, because the mean of its divisors is an integer number (22006565019).

Almost surely, 244013130037 is an apocalyptic number.

It is an amenable number.

44013130037 is a deficient number, since it is larger than the sum of its proper divisors (1).

44013130037 is an equidigital number, since it uses as much as digits as its factorization.

44013130037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 26.

The spelling of 44013130037 in words is "forty-four billion, thirteen million, one hundred thirty thousand, thirty-seven".