Base | Representation |
---|---|
bin | 110010000010011100110001… |
… | …1110011111010011000001011 |
3 | 2010201102002201021101010112021 |
4 | 1210010321203303322120023 |
5 | 430142233422234043311 |
6 | 4200034045334225311 |
7 | 161465106354436264 |
oct | 14404714363723013 |
9 | 2121362637333467 |
10 | 440141333112331 |
11 | 118273989098934 |
12 | 41446409ab5237 |
13 | 15b791c3936c66 |
14 | 7a98d5041196b |
15 | 35d4145aed171 |
hex | 1904e63cfa60b |
440141333112331 has 2 divisors, whose sum is σ = 440141333112332. Its totient is φ = 440141333112330.
The previous prime is 440141333112277. The next prime is 440141333112347. The reversal of 440141333112331 is 133211333141044.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-440141333112331 is a prime.
It is a super-2 number, since 2×4401413331123312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (440141333112361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220070666556165 + 220070666556166.
It is an arithmetic number, because the mean of its divisors is an integer number (220070666556166).
Almost surely, 2440141333112331 is an apocalyptic number.
440141333112331 is a deficient number, since it is larger than the sum of its proper divisors (1).
440141333112331 is an equidigital number, since it uses as much as digits as its factorization.
440141333112331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 440141333112331 its reverse (133211333141044), we get a palindrome (573352666253375).
The spelling of 440141333112331 in words is "four hundred forty trillion, one hundred forty-one billion, three hundred thirty-three million, one hundred twelve thousand, three hundred thirty-one".
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