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44022134131 is a prime number
BaseRepresentation
bin101000111111111011…
…000111010101110011
311012121222102010021021
4220333323013111303
51210124131243011
632120135040311
73115623652243
oct507773072563
9135558363237
1044022134131
111774038aa38
128646b10097
1341c74538a1
1421b8843b23
151229b80471
hexa3fec7573

44022134131 has 2 divisors, whose sum is σ = 44022134132. Its totient is φ = 44022134130.

The previous prime is 44022134099. The next prime is 44022134147. The reversal of 44022134131 is 13143122044.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 44022134131 - 25 = 44022134099 is a prime.

It is a super-2 number, since 2×440221341312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44022134096 and 44022134105.

It is not a weakly prime, because it can be changed into another prime (44022134161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22011067065 + 22011067066.

It is an arithmetic number, because the mean of its divisors is an integer number (22011067066).

Almost surely, 244022134131 is an apocalyptic number.

44022134131 is a deficient number, since it is larger than the sum of its proper divisors (1).

44022134131 is an equidigital number, since it uses as much as digits as its factorization.

44022134131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 44022134131 its reverse (13143122044), we get a palindrome (57165256175).

The spelling of 44022134131 in words is "forty-four billion, twenty-two million, one hundred thirty-four thousand, one hundred thirty-one".